`Đáp án:`
`A` = `1` +` 4` +$4^{2}$ + $4^{3}$ + ... + $4^{50}$
`=>` `4A` = `4` + $4^{2}$ + $4^{3}$ + ... +$4^{50}$ + $4^{51}$
`=>` `4A` - `A` = ( `4` +$4^{2}$ + $4^{3}$ + ... + $4^{50}$ +$4^{51}$ ) - ( `1` + `4` + $4^{2}$ +$4^{3}$ + ... + $4^{50}$ )
`=>` `3A `= $4^{51}$ - `1` => `A` = ($4^{51}$ - `1`) : `3`
$\text{Chúc bạn học tốt}$