Em tham khảo nha:
\(\begin{array}{l}
a)\\
{M_{Mg}} = \dfrac{{4 \times {{10}^{ - 23}}}}{{1,6605 \times {{10}^{ - 24}}}} = 24u\\
b)\\
{n_{Al}} = \dfrac{{540}}{{27}} = 20\,mol\\
{A_{Al}} = 20 \times 6 \times {10^{23}} = 1,2 \times {10^{25}}\\
c)\\
{n_{C{O_2}}} = \dfrac{{1,5 \times {{10}^{23}}}}{{6 \times {{10}^{23}}}} = 0,25\,mol\\
{m_{C{O_2}}} = 0,25 \times 44 = 11g\\
{V_{C{O_2}}} = 0,25 \times 22,4 = 5,6l\\
d)\\
{m_{{H_2}O}} = 1 \times 1 = 1000g\\
{n_{{H_2}O}} = \dfrac{{1000}}{{18}} = \dfrac{{500}}{9}\,mol\\
{A_{{H_2}O}} = \dfrac{{500}}{9} \times 6 \times {10^{23}} = 3,33 \times {10^{25}}\\
{A_H} = \dfrac{{500}}{9} \times 2 \times 6 \times {10^{23}} = 6,66 \times {10^{25}}
\end{array}\)