Đáp án:
`qquad C<D`
Giải thích các bước giải:
`C=(2+1).(2^2+1)(2^4+1).(2^8+1).(2^16+1)`
`=1.(2+1).(2^2+1)(2^4+1).(2^8+1).(2^16+1)`
`=(2-1).(2+1).(2^2+1)(2^4+1).(2^8+1).(2^16+1)`
`=(2^2-1).(2^2+1)(2^4+1).(2^8+1).(2^16+1)`
`=(2^4-1).(2^4+1).(2^8+1).(2^16+1)`
`=(2^8-1).(2^8+1).(2^16+1)`
`=(2^16-1).(2^16+1)`
`=2^31-1<2^32=D`
Vậy `C<D`