Đáp án:
1C
2 D
Giải thích các bước giải:
\(\begin{array}{l}
1)\\
{C_n}{H_{2n + 2}} + \dfrac{{3n + 1}}{2}{O_2} \xrightarrow{t^0} nC{O_2} + (n + 1){H_2}O\\
{n_{C{O_2}}} = \dfrac{{3,36}}{{22,4}} = 0,15\,mol\\
{n_{ankan}} = 0,15 \times \dfrac{1}{n} = \dfrac{3}{{20n}}\,mol\\
{M_{ankan}} = \dfrac{{2,2}}{{\dfrac{3}{{20n}}}} = \dfrac{{44n}}{3}\,g/mol\\
\Rightarrow 14n + 2 = \dfrac{{44n}}{3} \Rightarrow n = 3 \Rightarrow CTPT:{C_3}{H_8}\\
2)\\
{C_n}{H_{2n + 2}} + \dfrac{{3n + 1}}{2}{O_2} \xrightarrow{t^0}nC{O_2} + (n + 1){H_2}O\\
{n_{C{O_2}}} = \dfrac{{11,2}}{{22,4}} = 0,5\,mol\\
{n_{ankan}} = 0,5 \times \dfrac{1}{n} = \dfrac{1}{{2n}}\,mol\\
{M_{ankan}} = \dfrac{{7,2}}{{\dfrac{1}{{2n}}}} = 14,4ng/mol\\
\Rightarrow 14n + 2 = 14,4n \Rightarrow n = 5 \Rightarrow CTPT:{C_5}{H_{12}}
\end{array}\)
