Đáp án:
Giải thích các bước giải:
Zn(OH)2to→ZnO+H2OZn(OH)2→toZnO+H2O
2Fe(OH)3to→Fe2O3+3H2O2Fe(OH)3→toFe2O3+3H2O
moxit=6,02−1,17=4,85(g)moxit=6,02−1,17=4,85(g)
Gọi nZn(OH)2=xnZn(OH)2=x ; nFe(OH)3=ynFe(OH)3=y
Ta có hpt
{99x+107y=6,0281x+12.160=4,85{99x+107y=6,0281x+12.160=4,85 ⇔ {y=0,01x=0,05{y=0,01x=0,05
%mZn(OH)2=0,05.996,02mZn(OH)2=0,05.996,02 . 100% = 82,22%
%mFe(OH)3=0,01.1076,02mFe(OH)3=0,01.1076,02 . 100% = 17,78%
b, Zn(OH)2+2HCl→ZnCl2+2H2OZn(OH)2+2HCl→ZnCl2+2H2O
2Fe(OH)3+6HCl→2FeCl3+6H2O2Fe(OH)3+6HCl→2FeCl3+6H2O
=> nHCl=0,05.2+0,01.3=0,13(mol)nHCl=0,05.2+0,01.3=0,13(mol)
mHCl=0,13.36,5=4,745(g)mHCl=0,13.36,5=4,745(g)
==> mdd=4,745.100:14,6=32,5(g)mdd=4,745.100:14,6=32,5(g)
VHCl=32,51,15=28,26(ml)