Em tham khảo nha:
\(\begin{array}{l}
1)\\
N{H_3} + HCl \to N{H_4}Cl\\
N{H_4}Cl + NaOH \to NaCl + N{H_3} + {H_2}O\\
N{H_3} + HN{O_2} \to N{H_4}N{O_2}\\
N{H_4}N{O_2} \xrightarrow{t^0} {N_2} + 2{H_2}O\\
{N_2} + {O_2} \xrightarrow{t^0} 2NO\\
2NO + {O_2} \xrightarrow{t^0} 2N{O_2}\\
4N{O_2} + {O_2} + 2{H_2}O \to 4HN{O_3}\\
2)\\
a)\\
{(N{H_4})_2}S{O_4} + 2NaOH \to N{a_2}S{O_4} + 2N{H_3} + 2{H_2}O\\
N{H_4}^ + + O{H^ - } \to N{H_3} + {H_2}O\\
{n_{{{(N{H_4})}_2}S{O_4}}} = 0,15 \times 1 = 0,15\,mol\\
{n_{N{H_3}}} = 2{n_{{{(N{H_4})}_2}S{O_4}}} = 0,3\,mol\\
{V_{N{H_3}}} = 0,3 \times 22,4 = 6,72l
\end{array}\)