`#tnvt`
`a)2x.(x-1/7)=0`
`=>`$\left[\begin{matrix} 2x=0 \\ x-\dfrac{1}{7}=0\end{matrix}\right.$
`=>`$\left[\begin{matrix}x=0\\x=\dfrac{1}{7}\end{matrix}\right.$
Vậy `x\in{0;1/7}`
`b)|x-3,5|=|4,5-x|(\text{Chắc đề như này})`
`=>[(x-3.5=4.5-x),(x-3.5=x-4.5):}`
`=>[(2x=8),(-3.5=-4.5(\text{Loại})):}`
`=>x=4`
Vậy `x=4`
`c)|-x+3,5|=|x-4,5|`
`=>[(-x+3.5=x-4.5),(-x+3.5=4.5-x):}`
`=>[(2x=8),(3.5=4.5(\text{Loại})):}`
`=>x=4`
Vậy `x=4`