`5(3x-2)^2 - 3^3 : 3^2 = 2`
`5(3x-2)^2 - 27 : 9=2`
`5(3x-2)^2 - 3=2`
`5(3x-2)^2 =5`
`(3x-2)^2 =1`
`(3x-2)^2 = (±1)^2`
`=>`\(\left[ \begin{array}{l}3x-2=1\\3x-2=-1\end{array} \right.\)
`=>`\(\left[ \begin{array}{l}3x=3\\3x=1\end{array} \right.\)
`=>`\(\left[ \begin{array}{l}x=1\\x=\frac{1}{3}\end{array} \right.\)
Vậy `x ∈ {1/3 ; 3}`