Em tham khảo nha :
\(\begin{array}{l}
a)\\
N{a_2}S{O_4} + BaC{l_2} \to BaS{O_4} + 2NaCl\\
N{a_2}S{O_4} \to 2N{a^ + } + S{O_4}^{2 - }\\
BaC{l_2} \to B{a^{2 + }} + 2C{l^ - }\\
b)\\
HCl + NaOH \to NaCl + {H_2}O\\
HCl \to {H^ + } + C{l^ - }\\
NaOH \to N{a^ + } + O{H^ - }\\
c)\\
C{H_3}COONa + HCl \to C{H_3}COOH + NaCl\\
C{H_3}COONa \to C{H_3}CO{O^ - } + N{a^ + }\\
HCl \to {H^ + } + C{l^ - }\\
d)\\
N{a_2}C{O_3} + 2HCl \to 2NaCl + C{O_2} + {H_2}O\\
N{a_2}C{O_3} \to 2N{a^ + } + C{O_3}^{2 - }\\
HCl \to {H^ + } + C{l^ - }\\
e)\\
Ba{(OH)_2} + 2HCl \to BaC{l_2} + 2{H_2}O\\
HCl \to {H^ + } + C{l^ - }\\
Ba{(OH)_2} \to B{a^{2 + }} + 2O{H^ - }\\
f)\\
Ba{(OH)_2} + {H_2}S{O_4} \to BaS{O_4} + 2{H_2}O\\
Ba{(OH)_2} \to B{a^{2 + }} + 2O{H^ - }\\
{H_2}S{O_4} \to 2{H^ + } + S{O_4}^{2 - }
\end{array}\)
