Đáp án:
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Giải thích các bước giải:
$(2x+3)^2=\dfrac{9}{121}\\\Rightarrow(2x+3)^2=\left(\pm\dfrac{3}{11}\right)^{\large 2}\\\Rightarrow 2x+3=\pm\dfrac{3}{11}\\\Rightarrow 2x=\left\{\dfrac{-30}{11};\dfrac{-36}{11}\right\}\\\Rightarrow x=\left\{\dfrac{-15}{11};\dfrac{-18}{11}\right\}$
Vậy $x=\left\{\dfrac{-15}{11};\dfrac{-18}{11}\right\}$
$(3x-1)^3=\dfrac{-8}{27}\\\Rightarrow (3x-1)^3=\left(\dfrac{-2}{3}\right)^{\large 3}\\\Rightarrow 3x-1=\dfrac{-2}{3}\\\Rightarrow 3x=\dfrac13\\\Rightarrow x=\dfrac19$
Vậy $x=\dfrac19$.
