`text{Ta có:}`
`25-(x+5)=-315-(25-315)`
`⇔25-x-5=-315-25+315`
`⇔20-x=-25`
`⇔x=20-(-25)`
`⇔x=45`
`34+(21-x)=(374-30)-373`
`⇔34+21-x=374-30-373`
`⇔55-x=-29`
`⇔x= 55-(-29)`
`⇔x= 84`
`(15-x)+(x-12)=7-(-8+x)`
`⇔15-x+x-12=7+8-x`
`⇔3=15-x`
`⇔x=15-3`
`⇔x=12`
`⇔(x-6)` $\times$ `(3x-9)>0`
`⇔` \(\left[ \begin{array}{l}x-6=0\\3x-9=0\end{array} \right.\)