Bài `1`:
`a)` `(-2)^3 - 16/3 + 2020^0 + 4/3`
`= -8 - 16/3 + 1 + 4/3`
`= -40/3 + 7/3`
`= -11`
`b)` `(4^2 × 4^3 )/(2^10)`
`= ((2^2)^2 × (2^2)^3)/( 2^10 )`
`= ( 2^4 × 2^6 )/( 2^10 )`
`= ( 2^10 )/( 2^10 )`
`= 1`
Bài `2`:
`a)` `| x - 2 | = 5`
`=>` $\left[\begin{matrix} x - 2 = -5\\ x - 2 = 5\end{matrix}\right.$
`=>` $\left[\begin{matrix} x = -5 + 2\\ x = 5 + 2\end{matrix}\right.$
`=>` $\left[\begin{matrix} x = -3\\ x = 7\end{matrix}\right.$
`=>` `x = -3` hoặc `x = 7`
@ Rin
