Bạn tham khảo:
$a/$
$CuO+2HCl \to CuCl_2+H_2O$
$ZnO+2HCl \to ZnCl_2+H_2O$
$b/$
$n_{HCl}=0,2.3=0,6(mol)$
$n_{CuO}=a(mol)$
$n_{ZnO}=b(mol)$
$m_{hh}=80a+81b=24,2(1)$
$n_{HCl}=2a+2b=0,6(2)$
$(1)(2)$
$a=0,1$
$b=0,2$
$\%m_{CuO}=\dfrac{0,1.80}{24,2}.100\%=33,06\%$
$\%m_{ZnO}=\dfrac{0,2.81}{24,2}.100\%=66,94\%$
$c/$
$CuO+H_2SO_4 \to CuSO_4+H_2O$
$ZnO+H_2SO_4 \to ZnSO_4+H_2O$
$n_{H_2SO_4}=0,1+0,2=0,3(mol)$
$m_{ddH_2SO_4}=\dfrac{0,3.98.100}{24,5}=120(g)$