Đáp án+Giải thích các bước giải:
$\\1)\left|\dfrac{3}{2}-x\right|=\dfrac{1}{2}\\<=>\left[ \begin{array}{l}\dfrac{3}{2}-x=\dfrac{1}{2}\\\dfrac{3}{2}-x=-\dfrac{1}{2}\end{array} \right.\\<=>\left[ \begin{array}{l}x=\dfrac{3}{2}-\dfrac{1}{2}\\x=\dfrac{3}{2}+\dfrac{1}{2}\end{array} \right.\\<=>\left[ \begin{array}{l}x=1\\x=2\end{array} \right.$
$\\2)\left|\dfrac{2}{3}-x\right|=\dfrac{1}{2}\\<=>\left[ \begin{array}{l}\dfrac{2}{3}-x=\dfrac{1}{2}\\\dfrac{2}{3}-x=-\dfrac{1}{2}\end{array} \right.\\<=>\left[ \begin{array}{l}x=\dfrac{2}{3}-\dfrac{1}{2}\\x=\dfrac{2}{3}+\dfrac{1}{2}\end{array} \right.\\<=>\left[ \begin{array}{l}x=\dfrac{1}{6}\\x=\dfrac{7}{6}\end{array} \right.$
