Ta có :
$(3x-1)(2x-3)(x+5)=0$
$⇔ \left[ \begin{array}{l}3x-1=0\\2x-3=0\\x+5=0\end{array} \right.$
$⇔ \left[ \begin{array}{l}x=\dfrac{1}{3}\\x=\dfrac{3}{2}\\x=-5\end{array} \right.$
$(x+1)(x-1)=0$
$⇔ \left[ \begin{array}{l}x-1=0\\x+1=0\end{array} \right.$
$⇔ \left[ \begin{array}{l}x=1\\x=-1\end{array} \right.$