Đáp án:
$\begin{array}{l}
3.\left( {x - \dfrac{1}{2}} \right) - 5.\left( {x + \dfrac{3}{5}} \right) = - x + \dfrac{1}{5}\\
\Rightarrow 3.x - 3.\dfrac{1}{2} - 5.x - 5.\dfrac{3}{5} + x = \dfrac{1}{5}\\
\Rightarrow 3x - 5x + x - \dfrac{3}{2} - 3 = \dfrac{1}{5}\\
\Rightarrow - x = \dfrac{1}{5} + \dfrac{3}{2} + 3\\
\Rightarrow - x = \dfrac{{2 + 15 + 30}}{{10}}\\
\Rightarrow - x = \dfrac{{47}}{{10}}\\
\Rightarrow x = \dfrac{{ - 47}}{{10}}\\
Vậy\,x = \dfrac{{ - 47}}{{10}}
\end{array}$
