\(\frac{x}{{x + 3}} - \frac{1}{{3 - x}} = \frac{{3 - 5x}}{{{x^2} - 9}}\)
A.\(S = \left\{ 0 \right\}.\)
B.\(S = \left\{ 1 \right\}.\)
C.\(S = \left\{ 2 \right\}.\)
D.\(S = \left\{ { - 1} \right\}.\)

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