Đáp án:
Giải thích các bước giải:
`||3x+2|-2/3|=4/3`
`TH1:|3x+2|-2/3=-4/3`
`=>|3x+2|=-4/3+2/3`
`=>|3x+2|=-2/3`
Ta lại có
`|3x+2|>=0`
`=>` Loại
`TH2:|3x+2|-2/3=4/3`
`=>|3x+2|=4/3+2/3`
`=>|3x+2|=6/3`
`=>|3x+2|=2`
`=>`\(\left[ \begin{array}{l}3x+2=2\\3x+2=-2\end{array} \right.\)
`=>`\(\left[ \begin{array}{l}3x=0\\3x=-4\end{array} \right.\)
`=>`\(\left[ \begin{array}{l}x=0\\x=\dfrac{-4}{3}\end{array} \right.\)
Vậy `x in {0,-4/3}`
