/x + $\frac{3}{4}$ / - $\frac{1}{2}$ = 0
⇒ /x + $\frac{3}{4}$ / = $\frac{1}{2}$
⇒ \(\left[ \begin{array}{l}x +\frac{3}{4} = \frac{1}{2}\\x +\frac{3}{4} = -\frac{1}{2} \end{array} \right.\)
⇒ \(\left[ \begin{array}{l}x = \frac{1}{2} -\frac{3}{4}\\x = -\frac{1}{2} -\frac{3}{4}\end{array} \right.\)
⇒ \(\left[ \begin{array}{l}x=-\frac{1}{4}\\x=-\frac{5}{4}\end{array} \right.\)
Vậy x ∈ {$-\frac{1}{4}$ ; $-\frac{5}{4}$ }
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