$3\dfrac{1}{3}x+16\dfrac{3}{4}=-13,25$
$\to \dfrac{10}{3}x+\dfrac{67}{4}=\dfrac{-53}{4}$
$\to \dfrac{10}{3}x=\dfrac{-53}{4}-\dfrac{67}{4}$
$\to \dfrac{10}{3}x=\dfrac{-120}{4}$
$\to \dfrac{10}{3}x=-30$
$\to x=-30:\dfrac{10}{3}$
$\to x=-30.\dfrac{3}{10}$
$\to x=-9$
Vậy $x=-9$
$(3\dfrac{1}{2}+2x).2\dfrac{2}{3}=5\dfrac{1}{3}$
$\to (\dfrac{7}{2}+2x).\dfrac{8}{3}=\dfrac{16}{3}$
$\to \dfrac{7}{2}+2x=\dfrac{16}{3}:\dfrac{8}{3}$
$\to \dfrac{7}{2}+2x=\dfrac{16}{3}.\dfrac{3}{8}$
$\to \dfrac{7}{2}+2x=2$
$\to 2x=2-\dfrac{7}{2}$
$\to 2x=\dfrac{-3}{2}$
$\to x=\dfrac{-3}{2}:2$
$\to x=\dfrac{-3}{4}$
Vậy $x=\dfrac{-3}{4}$
$(\dfrac{3}{4}x+2\dfrac{1}{2}).\dfrac{-2}{3}=\dfrac{1}{8}$
$\to (\dfrac{3}{4}x+\dfrac{5}{2}).\dfrac{-2}{3}=\dfrac{1}{8}$
$\to \dfrac{3}{4}x+\dfrac{5}{2}=\dfrac{1}{8}:\dfrac{-2}{3}$
$\to \dfrac{3}{4}x+\dfrac{5}{2}=\dfrac{-3}{16}$
$\to \dfrac{3}{4}x=\dfrac{-3}{16}-\dfrac{5}{2}$
$\to \dfrac{3}{4}x=\dfrac{-43}{16}$
$\to x=\dfrac{-43}{16}:\dfrac{3}{4}$
$\to x=\dfrac{-43}{12}$
Vậy $x=\dfrac{-43}{12}$
