x+\(\dfrac{3}{15}=\dfrac{1}{3}\)

<=>\(x=\dfrac{1}{3}-\dfrac{3}{15}\)

<=>x=\(\dfrac{5}{15}-\dfrac{3}{15}\)

<=>x=\(\dfrac{2}{15}\)

Vậy S={\(\dfrac{2}{15}\)}

\(-5\left(x+\dfrac{1}{5}\right)-\dfrac{1}{2}\left(x-\dfrac{2}{3}\right)=\dfrac{3}{2}x-\dfrac{5}{6}\)

<=>\(-5x-1-\dfrac{1}{2}x+\dfrac{1}{3}=\dfrac{3}{2}x-\dfrac{5}{6}\)

<=>\(-\dfrac{11}{2}x-\dfrac{3}{2}x=-\dfrac{5}{6}+1-\dfrac{1}{3}\)

<=>-7x=\(-\dfrac{1}{6}\)

<=>x=\(\dfrac{7}{6}\)

Vậy S={\(\dfrac{7}{6}\)}

\(x\cdot6\dfrac{2}{7}+\dfrac{3}{7}\cdot2\dfrac{1}{5}-\dfrac{3}{7}=-2\)

<=>\(x\cdot\dfrac{44}{7}+\dfrac{3}{7}\cdot\dfrac{11}{5}-\dfrac{3}{7}=-2\)

<=>\(x\cdot\dfrac{44}{7}+\dfrac{3}{7}\cdot\left(\dfrac{11}{5}-1\right)=-2\)

<=>\(x\cdot\dfrac{44}{7}+\dfrac{3}{7}\cdot\dfrac{6}{5}=-2\)

<=>\(\dfrac{44}{7}x\)\(+\dfrac{18}{35}=-2\)

<=>\(\dfrac{44}{7}x=-2-\dfrac{18}{35}\)

<=>\(\dfrac{44}{7}x=-\dfrac{88}{35}\)

<=>x=\(-\dfrac{88}{35}\cdot\dfrac{7}{44}\)

<=>x=\(-\dfrac{2}{5}\)

Vậy S={\(-\dfrac{2}{5}\)}