Cho \({\log _2}3 = a\). Hãy tính \({\log _4}54\) theo \(a\).
A.\({\log _4}54 = \frac{1}{2}\left( {1 + 3a} \right)\).
B.\({\log _4}54 = \frac{1}{2}\left( {1 + 6a} \right)\).
C.\({\log _4}54 = \frac{1}{2}\left( {1 + 12a} \right)\).
D. \({\log _4}54 = 2\left( {1 + 6a} \right)\).
A.\({\log _4}54 = \frac{1}{2}\left( {1 + 3a} \right)\).
B.\({\log _4}54 = \frac{1}{2}\left( {1 + 6a} \right)\).
C.\({\log _4}54 = \frac{1}{2}\left( {1 + 12a} \right)\).
D. \({\log _4}54 = 2\left( {1 + 6a} \right)\).
Loga
Hóa Học lớp 12
