Đáp án đúng: A
Giải chi tiết:\(\begin{array}{l}\frac{3}{5}.\left( {2x - \frac{1}{3}} \right) + \frac{4}{{15}} = \,\frac{{12}}{{30}}\,\,\,\,\,\,\,\,\,\\ \Leftrightarrow \frac{3}{5}.\left( {2x - \frac{1}{3}} \right) = \,\frac{{12}}{{30}} - \frac{4}{{15}}\,\,\,\,\,\,\,\,\,\\ \Leftrightarrow \frac{3}{5}.\left( {2x - \frac{1}{3}} \right) = \,\frac{6}{{15}} - \frac{4}{{15}}\,\,\,\,\\ \Leftrightarrow \frac{3}{5}.\left( {2x - \frac{1}{3}} \right) = \,\frac{2}{{15}}\,\,\,\,\,\,\,\,\,\,\\ \Leftrightarrow \,2x - \frac{1}{3} = \frac{2}{{15}}:\frac{3}{5}\,\,\,\,\,\,\,\,\,\\ \Leftrightarrow 2x - \frac{1}{3} = \frac{2}{9}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\\ \Leftrightarrow 2x = \frac{2}{9} + \frac{1}{3}\,\,\,\,\,\,\,\\\, \Leftrightarrow \,2x = \frac{5}{9}\\\, \Leftrightarrow x = \frac{5}{9}:2\\\, \Leftrightarrow \,x = \frac{5}{{18}}\end{array}\)
Chọn A.
