\(\begin{array}{l}
Ap\,\,dung\,\,dinh\,\,ly\,\,Pitago\,\,ta\,\,co:\\
BC = \sqrt {A{B^2} + A{C^2}} = \sqrt {1,{8^2} + {3^2}} = \frac{{3\sqrt {34} }}{5}.\\
\tan \angle B = \frac{{AC}}{{AB}} = \frac{3}{{1,8}} = \frac{5}{3} \Rightarrow \angle B \approx {59^0}\\
\Rightarrow \angle C = {180^0} - \angle A - \angle B = {180^0} - {90^0} - {59^0} = {31^0}.
\end{array}\)