Hoàn chỉnh phản ứng sau: ${}_0^1n + {}_{92}^{235}U \to {}_?^{95}Zn + {}_{52}^{138}Te + x\left( {{}_0^1n} \right)$
A.$_0^1{\text{n}} + {\text{ }}_{92}^{235}{\text{U}} \to {\text{ }}_{40}^{95}{\text{Zn}} + {\text{ }}_{52}^{138}{\text{Te }} + 2({}_0^1{\text{n }})$
B.$_0^1{\text{n}} + {\text{ }}_{92}^{235}{\text{U}} \to {\text{ }}_{40}^{95}{\text{Zn}} + {\text{ }}_{52}^{138}{\text{Te }} + 3({}_0^1{\text{n }})$
C.$_0^1{\text{n}} + {\text{ }}_{92}^{235}{\text{U}} \to {\text{ }}_{40}^{95}{\text{Zn}} + {\text{ }}_{53}^{138}{\text{Te }} + 3({}_0^1{\text{n }})$
D.$_0^1{\text{n}} + {\text{ }}_{92}^{235}{\text{U}} \to {\text{ }}_{40}^{95}{\text{Zn}} + {\text{ }}_{53}^{138}{\text{Te }} + 2({}_0^1{\text{n }})$
A.$_0^1{\text{n}} + {\text{ }}_{92}^{235}{\text{U}} \to {\text{ }}_{40}^{95}{\text{Zn}} + {\text{ }}_{52}^{138}{\text{Te }} + 2({}_0^1{\text{n }})$
B.$_0^1{\text{n}} + {\text{ }}_{92}^{235}{\text{U}} \to {\text{ }}_{40}^{95}{\text{Zn}} + {\text{ }}_{52}^{138}{\text{Te }} + 3({}_0^1{\text{n }})$
C.$_0^1{\text{n}} + {\text{ }}_{92}^{235}{\text{U}} \to {\text{ }}_{40}^{95}{\text{Zn}} + {\text{ }}_{53}^{138}{\text{Te }} + 3({}_0^1{\text{n }})$
D.$_0^1{\text{n}} + {\text{ }}_{92}^{235}{\text{U}} \to {\text{ }}_{40}^{95}{\text{Zn}} + {\text{ }}_{53}^{138}{\text{Te }} + 2({}_0^1{\text{n }})$
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Hóa Học lớp 12
