Giải hệ phương trình : \(\left\{ \begin{array}{l}\left( {{x^2} + x} \right){y^2} - 4{y^2} + y + 1 = 0\\xy + {x^2}{y^2} + 1 - \left( {4 - {x^3}} \right){y^3} = 0\end{array} \right.\)
A.\(\left( {x;y} \right) = \left( {-1;-1} \right)\).
B.\(\left( {x;y} \right) = \left( {1;-1} \right)\).
C.\(\left( {x;y} \right) = \left( {-1;1} \right)\).
D.\(\left( {x;y} \right) = \left( {1;1} \right)\).
A.\(\left( {x;y} \right) = \left( {-1;-1} \right)\).
B.\(\left( {x;y} \right) = \left( {1;-1} \right)\).
C.\(\left( {x;y} \right) = \left( {-1;1} \right)\).
D.\(\left( {x;y} \right) = \left( {1;1} \right)\).
Loga
Hóa Học lớp 12
