Đáp án đúng: D
Giải chi tiết:2CH3OH \(\buildrel {{H_2}S{O_4}\,\,dac,\,{{170}^0}C} \over\longrightarrow \) CH3-O-CH3+ H2O
2CH3-CH2-CH2OH \(\buildrel {{H_2}S{O_4}\,\,dac,\,{{170}^0}C} \over\longrightarrow \) CH3-CH2-CH2OCH2-CH2-CH3 + H2O
2CH3CH(OH)CH3 \(\buildrel {{H_2}S{O_4}\,\,dac,\,{{170}^0}C} \over\longrightarrow \) (CH3)2CH-O-CH(CH3)2+ H2O
CH3OH + CH3-CH2-CH2OH \(\buildrel {{H_2}S{O_4}\,\,dac,\,{{170}^0}C} \over\longrightarrow \) CH3-CH2-CH2-O-CH3+ H2O
CH3OH + CH3CH(OH)CH3 \(\buildrel {{H_2}S{O_4}\,\,dac,\,{{170}^0}C} \over\longrightarrow \) CH3-O-CH(CH3)2+ H2O
CH3-CH2-CH2OH+ CH3CH(OH)CH3 \(\buildrel {{H_2}S{O_4}\,\,dac,\,{{170}^0}C} \over\longrightarrow \) CH3-CH2-CH2OCH(CH3)2+ H2O
CH3-CH2-CH2-OH \(\buildrel {{H_2}S{O_4}\,\,dac,\,{{170}^0}C} \over\longrightarrow \) CH3-CH=CH2+ H2O
CH3CH(OH)CH3 \(\buildrel {{H_2}S{O_4}\,\,dac,\,{{170}^0}C} \over\longrightarrow \)CH3-CH=CH2+ H2O
Vậy thu được tối đa 7 sản phẩm hữu cơ (gồm có 6 ete và 1 anken)
Đáp án D
