$\begin{array}{l}
A\left( {0;1} \right) \in d,{D_I}\left( A \right) = A' \Rightarrow A'\left( {2x;2y - 1} \right) \in d'\\
\Leftrightarrow 5.2x - 2.\left( {2y - 1} \right) - 10 = 0 \Leftrightarrow 10x - 4y - 8 = 0\\
B\left( {1;0} \right) \in Ox,{D_I}\left( B \right) = B' \Rightarrow A'\left( {2x - 1;2y} \right) \in Ox\\
\Leftrightarrow 2y = 0 \Leftrightarrow y = 0\\
\Rightarrow 10x - 4.0 - 8 = 0 \Leftrightarrow x = \frac{4}{5} \Rightarrow I\left( {\frac{4}{5};0} \right)
\end{array}$
Câu b làm tương tự bạn nhé!