Đáp án:
A: Al, Al2S3, S
B: AlCl3, HCl
E: S
F: H2, H2S
H: NaAlO2, NaOH
T: CuS
Q: MgO, CuO, Cu
Giải thích các bước giải:
$2Al + 3S \xrightarrow{t^o} Al_2S_3$
Chất rắn A: Al, Al2S3, S
$2Al + 6HCl → 2AlCl_3 + 3H_2↑$
$Al_2S_3 + 6HCl → 2AlCl_3 + 3H_2S↑$
B: AlCl3, HCl; E: S; F: H2, H2S
$2Al + 2NaOH + 2H_2O → 2NaAlO_2 + 3H_2↑$
$Al_2S_3 + H_2O → Al(OH)_3 + H_2S↑$
$Al(OH)_3 + NaOH → NaAlO_2 + 2H_2O$
H: NaAlO2, NaOH
$H_2S + Cu(NO_3)_2 → CuS ↓ + 2HNO_3$
T: CuS
$H_2 + CuO \xrightarrow{t^o} Cu + H_2O$
Q: MgO, CuO, Cu
$MgO + H_2SO_4 → MgSO_4 + H_2O$
$CuO + H_2SO_4 → CuSO_4 + H_2O$