Đáp án đúng: C
Giải chi tiết:Đường tròn \((C):{{(x-2)}^{2}}+{{(y+1)}^{2}}=9\) có tâm \(I=(2;-1)\), bán kính \(R=3\).
\(\begin{align} {{V}_{\left( O;\frac{-1}{3} \right)}}:\,\,(C)\,\,\,\mapsto ({{C}_{0}}) \\ \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,R\,\,\,\,\mapsto \,{{R}_{0}} \\ \end{align}\)
Sao cho: \({{R}_{0}}=\left| \frac{-1}{3} \right|R=\frac{1}{3}R=\frac{1}{3}.3=1\)
\(\begin{align} {{T}_{\overrightarrow{v}}}:\,\,\,\,\,({{C}_{0}})\,\,\,\mapsto \,\,(C') \\ \,\,\,\,\,\,\,\,\,\,\,{{R}_{0}}\,\,\,\,\,\,\,\mapsto \,\,\,R' \\ \end{align}\)
Sao cho : \(R'={{R}_{0}}=1\).
Chọn: C