Tham khảo
Đặt `A=\frac{4}{1.5}+\frac{4}{5.9}+...+\frac{4}{101.105}`
Áp dụng `\frac{4}{n(n+4)}=\frac{1}{n}-\frac{1}{n+4}`
`⇒A=1-\frac{1}{5}+\frac{1}{5}-\frac{1}{9}+...+\frac{1}{101}-\frac{1}{105}`
`⇒A=1-\frac{1}{105}`
`⇒A=\frac{104}{105}`
`\text{©CBT}`