Đáp án:
\(\left[ \begin{array}{l}x=4\\x=\dfrac{19}{4}\end{array} \right.\)
Giải thích các bước giải:
$4x^2-35x+76=0$
$⇔(4x^2-16x)-(19x-76)=0$
$⇔4x.(x-4)-19.(x-4)=0$
$⇔(x-4).(4x-19)=0$
$⇔\(\left[ \begin{array}{l}x-4=0\\4x-19=0\end{array} \right.\) $
$⇔\(\left[ \begin{array}{l}x=4\\4x=19\end{array} \right.\) $
$⇔\(\left[ \begin{array}{l}x=4\\x=\dfrac{19}{4}\end{array} \right.\) $
