Đáp án:
a) `x∈{7/3;1/3}`
b) `x∈{- 7/24;1/48}`
Giải thích các bước giải:
a) `|x-4/3|-2/5=3/5`
`→|x-4/3|=1`
`→`\(\left[ \begin{array}{l}x-\dfrac{4}{3}=1\\x-\dfrac{4}{3}=-1\end{array} \right.\)
`→`\(\left[ \begin{array}{l}x=\dfrac{7}{3}\\x=\dfrac{1}{3}\end{array} \right.\)
Vậy: `x∈{7/3;1/3}`
b) `|x-1/3|-|3x+1/4|=0`
`→|x-1/3|=|3x+1/4|`
`→`\(\left[ \begin{array}{l}x-\dfrac{1}{3}=3x+\dfrac{1}{4}\\x-\dfrac{1}{3}=-3x-\dfrac{1}{4}\end{array} \right.\)
`→`\(\left[ \begin{array}{l}x-3x=\dfrac{1}{3}+\dfrac{1}{4}\\x+3x=\dfrac{1}{3}-\dfrac{1}{4}\end{array} \right.\)
`→`\(\left[ \begin{array}{l}-2x=\dfrac{7}{12}\\4x=\dfrac{1}{12}\end{array} \right.\)
`→`\(\left[ \begin{array}{l}x=-\dfrac{7}{24}\\x=\dfrac{1}{48}\end{array} \right.\)
Vậy: `x∈{- 7/24;1/48}`
