Nghiệm của phương trình \( \sin \left( {2x + \frac{ \pi }{6}} \right) = \frac{{ \sqrt 3 }}{2} \) là:
A.\(\left[ \begin{array}{l}x = \frac{\pi }{{12}} + k\pi \\x = - \frac{\pi }{4} + k\pi \end{array} \right.\;\;\left( {k \in Z} \right)\)
B.\(\left[ \begin{array}{l}x = \frac{\pi }{{12}} + k\pi \\x = \frac{\pi }{4} + k\pi \end{array} \right.\;\left( {k \in Z} \right)\)
C.\(\left[ \begin{array}{l}x = \frac{\pi }{{12}} + k2\pi \\x = \frac{\pi }{4} + k2\pi \end{array} \right.\;\left( {k \in Z} \right)\)
D.\(\left[ \begin{array}{l}x = \frac{\pi }{{12}} + k2\pi \\x = - \frac{\pi }{4} + k2\pi \end{array} \right.\;\;\left( {k \in Z} \right)\)
A.\(\left[ \begin{array}{l}x = \frac{\pi }{{12}} + k\pi \\x = - \frac{\pi }{4} + k\pi \end{array} \right.\;\;\left( {k \in Z} \right)\)
B.\(\left[ \begin{array}{l}x = \frac{\pi }{{12}} + k\pi \\x = \frac{\pi }{4} + k\pi \end{array} \right.\;\left( {k \in Z} \right)\)
C.\(\left[ \begin{array}{l}x = \frac{\pi }{{12}} + k2\pi \\x = \frac{\pi }{4} + k2\pi \end{array} \right.\;\left( {k \in Z} \right)\)
D.\(\left[ \begin{array}{l}x = \frac{\pi }{{12}} + k2\pi \\x = - \frac{\pi }{4} + k2\pi \end{array} \right.\;\;\left( {k \in Z} \right)\)
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Hóa Học lớp 12
