Đáp án đúng: B
Giải chi tiết:\(A.\,nC{H_2} = C{H_2}\buildrel {{t^0},p,xt} \over \longrightarrow {( - C{H_2} - C{H_2} - )_n}\)
\(B.n{H_2}N - {{\rm{[}}C{H_2}]_6} - N{H_2} + HOOC - {{\rm{[}}C{H_2}]_4} - COOH\buildrel {{t^0},p,xt} \over \longrightarrow {( - NH - {{\rm{[}}C{H_2}]_6} - NH - CO - {\rm{[}}C{H_2}] - CO - )_n} + 2n{H_2}O\)
\(C.\,C{H_2} = CH(C{H_3}) - COOC{H_3}\buildrel {{t^0},p,xt} \over \longrightarrow ( - C{H_2} - \mathop C\limits_{\scriptstyle \,\,\,\,\,\,\,\,\,| \hfill \atop \scriptstyle \,\,\,\,\,\,OOCH3 \hfill} ^{\scriptstyle C{H_3} \hfill \atop \scriptstyle \,\,\,\,| \hfill} {H_2} - )n\)
\(D.\,\,nC{H_2} = CHCl\buildrel {{t^0},p,xt} \over \longrightarrow ( - C{H_2} - \mathop C\limits_{\scriptstyle \,\,\,\,\,\, \hfill \atop \scriptstyle Cl \hfill} H - )n\)
Đáp án B