B=\(\dfrac{3}{4}\).b+\(\dfrac{4}{3}\).b-\(\dfrac{1}{2}\).b với b=\(\dfrac{6}{19}\)
C=c.\(\dfrac{3}{4}\)+c.\(\dfrac{5}{6}\)-c.\(\dfrac{19}{12}\) với c=\(\dfrac{2002}{2003}\)
Loga
Toán lớp 6
B=\(\dfrac{3}{4}\).b+\(\dfrac{4}{3}\).b-\(\dfrac{1}{2}\).b với b=\(\dfrac{6}{19}\)
C=c.\(\dfrac{3}{4}\)+c.\(\dfrac{5}{6}\)-c.\(\dfrac{19}{12}\) với c=\(\dfrac{2002}{2003}\)
