Đáp án đúng: B
Giải chi tiết:\(\begin{array}{l}\,\frac{{{9^8}{{.8}^6}}}{{{{16}^4}{{.3}^{17}}}} = \frac{{{{\left( {{3^2}} \right)}^8}.{{\left( {{2^3}} \right)}^6}}}{{{{\left( {{2^4}} \right)}^4}{{.3}^{17}}}}\\\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = \frac{{{3^{16}}{{.2}^{18}}}}{{{2^{16}}{{.3}^{16}}.3}}\\\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = \frac{{{2^2}}}{3}\\\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = \frac{4}{3}\end{array}\)
Chọn B