\( \mathop { \lim } \limits_{x \to 3} \left( { \dfrac{{3{x^2}}}{{x - 3}}. \dfrac{{12x + 4}}{{2{x^3} - 6{x^2} + x - 3}}} \right) \) bằng:
A.\( + \infty \)                            
B.\(\dfrac{{12}}{5}\)                
C.\(1\)                                        
D.\( - \infty \)

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