Đáp án:
$\begin{array}{l}
B = \left( {x.\sqrt {\frac{6}{x}} + \frac{{2x}}{3} + \sqrt {6x} } \right):\sqrt {6x} \left( {dkxd:x > 0} \right)\\
= \left( {\sqrt {6x} + \frac{{6x}}{9} + \sqrt {6x} } \right):\sqrt {6x} \\
= \left[ {\sqrt {6x} .\left( {2 + \frac{{\sqrt {6x} }}{9}} \right)} \right]:\sqrt {6x} \\
= 2 + \frac{{\sqrt {6x} }}{9}
\end{array}$