Đạo hàm của hàm số \(y = \tan \left( {{x^2} + 2 \sqrt x + 1} \right) \) là:
A.\(y' = \frac{{2x\sqrt x + 1}}{{\sqrt x \cos \left( {{x^2} + 2\sqrt x + 1} \right)}}\)
B.\(y' = \frac{{2x\sqrt x + 1}}{{\sqrt x {{\cos }^2}\left( {{x^2} + 2\sqrt x + 1} \right)}}\)
C.\(y' = \frac{{2x\sqrt x + 1}}{{x\cos \left( {{x^2} + 2\sqrt x + 1} \right)}}\)
D.\(y' = \frac{{2x\sqrt x + 1}}{{x{{\cos }^2}\left( {{x^2} + 2\sqrt x + 1} \right)}}\)
A.\(y' = \frac{{2x\sqrt x + 1}}{{\sqrt x \cos \left( {{x^2} + 2\sqrt x + 1} \right)}}\)
B.\(y' = \frac{{2x\sqrt x + 1}}{{\sqrt x {{\cos }^2}\left( {{x^2} + 2\sqrt x + 1} \right)}}\)
C.\(y' = \frac{{2x\sqrt x + 1}}{{x\cos \left( {{x^2} + 2\sqrt x + 1} \right)}}\)
D.\(y' = \frac{{2x\sqrt x + 1}}{{x{{\cos }^2}\left( {{x^2} + 2\sqrt x + 1} \right)}}\)
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Hóa Học lớp 12
