a/ \(\left(x-2\right)\left(y+1\right)=7\)

\(\Leftrightarrow x-2;y+1\inƯ\left(7\right)\)

\(\Leftrightarrow\left[{}\begin{matrix}\left\{{}\begin{matrix}x-2=1\\y+1=7\end{matrix}\right.\\\left\{{}\begin{matrix}x-2=7\\y+1=1\end{matrix}\right.\\\left\{{}\begin{matrix}x-2=-1\\y+1=-7\end{matrix}\right.\\\left\{{}\begin{matrix}x-2=-7\\y+1=-1\end{matrix}\right.\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}\left\{{}\begin{matrix}x=3\\y=6\end{matrix}\right.\\\left\{{}\begin{matrix}x=9\\y=0\end{matrix}\right.\\\left\{{}\begin{matrix}x=1\\y=-8\end{matrix}\right.\\\left\{{}\begin{matrix}x=-5\\y=-2\end{matrix}\right.\end{matrix}\right.\)

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b/ \(\left(2x-1\right)y-2x+1=3\)

\(\Leftrightarrow\left(2x-1\right)y-\left(2x-1\right)=3\)

\(\Leftrightarrow\left(2x-1\right)\left(y-1\right)=3\)

\(\Leftrightarrow\left[{}\begin{matrix}\left\{{}\begin{matrix}2x-1=1\\y-1=3\end{matrix}\right.\\\left\{{}\begin{matrix}2x-1=3\\y-1=1\end{matrix}\right.\\\left\{{}\begin{matrix}2x-1=-1\\y-1=-3\end{matrix}\right.\\\left\{{}\begin{matrix}2x-1=-3\\y-1=-1\end{matrix}\right.\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}\left\{{}\begin{matrix}x=1\\y=4\end{matrix}\right.\\\left\{{}\begin{matrix}x=2\\y=2\end{matrix}\right.\\\left\{{}\begin{matrix}x=0\\y=-1\end{matrix}\right.\\\left\{{}\begin{matrix}x=-1\\y=0\end{matrix}\right.\end{matrix}\right.\)

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