Giải thích các bước giải:
a.$\dfrac{(x+5)^2-9}{x^2+4x+4}$
$=\dfrac{(x+5)^2-3^2}{(x+2)^2}$
$=\dfrac{(x+5-3)(x+5+3)}{(x+2)^2}$
$=\dfrac{(x+2)(x+8)}{(x+2)^2}$
$=\dfrac{x+8}{x+2}$
b.$\dfrac{2-x}{x-6}+\dfrac{36}{x^2-6x}$
$=\dfrac{x(2-x)}{x(x-6)}+\dfrac{36}{x(x-6)}$
$=\dfrac{x(2-x)+36}{x(x-6)}$
$=\dfrac{2x-x^2+36}{x(x-6)}$