\(\left(2x-3\right)^2=26\Leftrightarrow\left\{{}\begin{matrix}2x-3=\sqrt{26}\\2x-3=-\sqrt{26}\end{matrix}\right.\) \(\Leftrightarrow\left\{{}\begin{matrix}2x=\sqrt{26}+3\\2x=-\sqrt{26}+3\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x=\dfrac{\sqrt{26}+3}{2}\\x=\dfrac{3-\sqrt{26}}{2}\end{matrix}\right.\) vậy \(x=\dfrac{\sqrt{26}+3}{2};x=\dfrac{3-\sqrt{26}}{2}\)
