Đáp án:
1.
a.
\(\begin{array}{l}
{v_d} = 5m/s\\
{v_n} = 2m/s
\end{array}\)
b. \({v_{tb}} = 2,857m/s\)
2. p=64000pa
Giải thích các bước giải:
\(\begin{array}{l}
1.\\
{s_d} = 50m,{t_d} = 10s,{v_n} = 50m,{t_n} = 25s\\
a.\\
{v_d} = \frac{{{s_d}}}{{{t_d}}} = \frac{{50}}{{10}} = 5m/s\\
{v_n} = \frac{{{s_n}}}{{{t_n}}} = \frac{{50}}{{25}} = 2m/s\\
b.\\
{v_{tb}} = \frac{{{s_d} + {s_n}}}{{{t_d} + {t_n}}} = \frac{{50 + 50}}{{10 + 25}} = 2,857m/s\\
2.\\
{P_n} = 600N,{P_G} = 40N,s = 100c{m^2} = 0,01{m^2}\\
p = \frac{F}{s} = \frac{{{P_n} + {P_G}}}{s} = \frac{{600 + 40}}{{0,01}} = 64000pa
\end{array}\)
