Đáp án:
+ $x= -11$
++ $x= -4 \veebar x= 12$
+++ $x= -4 \veebar x= 14$
Giải thích các bước giải:
+ $\dfrac{5-2x}{3}= \dfrac{4x-1}{-5}$
$\Rightarrow -25+10x= 12x-3$
$\Rightarrow -2x= 22\Rightarrow x= -11$
++ $\dfrac{12-3x}{32}= \dfrac{6}{4-x}$
$\Rightarrow \dfrac{3\left ( 4-x \right )}{32}= \dfrac{6}{4-x}$
$\Rightarrow \left ( 4-x \right )^{2}= 64$
$\Rightarrow 4-x= \pm 8\Rightarrow x= -4 \veebar x= 12$
+++ $\dfrac{10-2x}{6}= \dfrac{27}{5-x}$
$\Rightarrow \dfrac{2\left ( 5-x \right )}{6}= \dfrac{27}{5-x}$
$\Rightarrow \left ( 5-x \right )^{2}= 81$
$\Rightarrow 5-x= \pm 9$
$\Rightarrow x= -4 \veebar x= 14$
