Đáp án:
$\text{ $\dfrac{x+5}{4}$ - $\dfrac{2x-3}{3}$ = $\dfrac{6x-1}{3}$ + $\dfrac{2x-1}{12}$ }$
$\text{⇔ $\dfrac{3(x+5)}{12}$ - $\dfrac{4(2x-3)}{12}$ = $\dfrac{4(6x-1)}{12}$ + $\dfrac{2x-1}{12}$ }$
$\text{⇔ 3(x+5) - 4(2x-3) = 4(6x-1) + 2x-1 }$
$\text{⇔ 3x+15 - 8x +12 = 24x -4 +2x-1 }$
$\text{⇔ 3x -8x -24x -2x = -1 -4 -12 -15 }$
$\text{⇔-31x = -32 }$
$\text{⇔ x = -32 : (-31) }$
$\text{⇔ x = $\dfrac{32}{31}$ }$
$\text{Vậy phương trình có tập nghiệm S={ $\dfrac{32}{31}$ } }$
