Đáp án:
`S={-4,-5,-6}.`
Giải thích các bước giải:
`\root{3}{5+x}-x=5`
`<=>\root{3}{5+x}=x+5`
`<=>x+5-\root{3}{5+x}=0`
`<=>\root{3}{x+5}^3-\root{3}{x+5}=0`
`<=>\root{3}{x+5}(\root{3}{(x+5)^2}-1)=0`
`<=>[(\root{3}{x+5}=0),(\root{3}{(x+5)^2}=1):}`
`<=>[(x+5=0),((x+5)^2=1):}`
`<=>[(x+5=0),(x+5=1),(x+5=-1):}`
`<=>[(x=-5),(x=-4),(x=-6):}`
Vậy `S={-4,-5,-6}.`