Đáp án:
$1^{25}:11^{23}-3^5:(1^{10}+2^3)-60$ $=\dfrac{1}{11^{23}}-87$
Giải thích các bước giải:
$1^{25}:11^{23}-3^5:(1^{10}+2^3)-60$
$=1:11^{23}-3^5:(1+8)-60$
$=\dfrac{1}{11^{23}}-3^5:9-60$
$=\dfrac{1}{11^{23}}-3^5:3^2-60$
$=\dfrac{1}{11^{23}}-3^{5-2}-60$
$=\dfrac{1}{11^{23}}-3^{3}-60$
$=\dfrac{1}{11^{23}}-27-60$
$=\dfrac{1}{11^{23}}-(27+60)$
$=\dfrac{1}{11^{23}}-87$
