Đáp án đúng: B
Giải chi tiết:Phản ứng:
\(\begin{gathered} C{H_3}COOC{H_3} + NaOH\xrightarrow{{{t^0}}}C{H_3}COONa + C{H_3}OH \hfill \\ \,\,\,\,\,\,\,\,\,0,07mol\,\,\,\,\,\,\,\,0,1mol\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,0,07mol\,\,\,\,\,\,\,\,\,\,\,0,07 \hfill \\ \end{gathered} \)
BTKL => m rắn khan = mCH3COOCH3+mNaOH-mCH3OH = 0,07.74+0,1.40-0,07.32=6,94 gam
Đáp án B