Đáp án:
$M=\dfrac{a^{2019}+a^{2019}+a^{2019}}{a^{672}.a^{673}.a^{674}}=3$
Giải thích các bước giải:
$\dfrac{a}{b}=\dfrac{b}{c}=\dfrac{c}{a}=\dfrac{a+b+c}{b+c+a}=1$
$\rightarrow a=b=c$
$\rightarrow M=\dfrac{a^{2019}+a^{2019}+a^{2019}}{a^{672}.a^{673}.a^{674}}$
$\rightarrow M=\dfrac{3a^{2019}}{a^{672+673+674}}$
$\rightarrow M=\dfrac{3a^{2019}}{a^{2019}}$
$\rightarrow M=3$